(X+2)(2x^2-x+3)=0

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Solution for (X+2)(2x^2-x+3)=0 equation: 


Simplifying
(X + 2)(2x2 + -1x + 3) = 0

Reorder the terms:
(2 + X)(2x2 + -1x + 3) = 0

Reorder the terms:
(2 + X)(3 + -1x + 2x2) = 0

Multiply (2 + X) * (3 + -1x + 2x2)
(2(3 + -1x + 2x2) + X(3 + -1x + 2x2)) = 0
((3 * 2 + -1x * 2 + 2x2 * 2) + X(3 + -1x + 2x2)) = 0
((6 + -2x + 4x2) + X(3 + -1x + 2x2)) = 0
(6 + -2x + 4x2 + (3 * X + -1x * X + 2x2 * X)) = 0
(6 + -2x + 4x2 + (3X + -1xX + 2x2X)) = 0

Reorder the terms:
(6 + 3X + -2x + -1xX + 4x2 + 2x2X) = 0
(6 + 3X + -2x + -1xX + 4x2 + 2x2X) = 0

Solving
6 + 3X + -2x + -1xX + 4x2 + 2x2X = 0

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + 3X + -2x + -1xX + 4x2 + -6 + 2x2X = 0 + -6

Reorder the terms:
6 + -6 + 3X + -2x + -1xX + 4x2 + 2x2X = 0 + -6

Combine like terms: 6 + -6 = 0
0 + 3X + -2x + -1xX + 4x2 + 2x2X = 0 + -6
3X + -2x + -1xX + 4x2 + 2x2X = 0 + -6

Combine like terms: 0 + -6 = -6
3X + -2x + -1xX + 4x2 + 2x2X = -6

Add '2x' to each side of the equation.
3X + -2x + -1xX + 4x2 + 2x + 2x2X = -6 + 2x

Reorder the terms:
3X + -2x + 2x + -1xX + 4x2 + 2x2X = -6 + 2x

Combine like terms: -2x + 2x = 0
3X + 0 + -1xX + 4x2 + 2x2X = -6 + 2x
3X + -1xX + 4x2 + 2x2X = -6 + 2x

Add '-4x2' to each side of the equation.
3X + -1xX + 4x2 + -4x2 + 2x2X = -6 + 2x + -4x2

Combine like terms: 4x2 + -4x2 = 0
3X + -1xX + 0 + 2x2X = -6 + 2x + -4x2
3X + -1xX + 2x2X = -6 + 2x + -4x2

Reorder the terms:
6 + 3X + -2x + -1xX + 4x2 + 2x2X = -6 + 2x + -4x2 + 6 + -2x + 4x2

Reorder the terms:
6 + 3X + -2x + -1xX + 4x2 + 2x2X = -6 + 6 + 2x + -2x + -4x2 + 4x2

Combine like terms: -6 + 6 = 0
6 + 3X + -2x + -1xX + 4x2 + 2x2X = 0 + 2x + -2x + -4x2 + 4x2
6 + 3X + -2x + -1xX + 4x2 + 2x2X = 2x + -2x + -4x2 + 4x2

Combine like terms: 2x + -2x = 0
6 + 3X + -2x + -1xX + 4x2 + 2x2X = 0 + -4x2 + 4x2
6 + 3X + -2x + -1xX + 4x2 + 2x2X = -4x2 + 4x2

Combine like terms: -4x2 + 4x2 = 0
6 + 3X + -2x + -1xX + 4x2 + 2x2X = 0

The solution to this equation could not be determined.

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